Prove |xy|=|x||y| with cases
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Prove |xy|=|x||y| with cases

[From: ] [author: ] [Date: 12-12-04] [Hit: ]
..So yeah, any time you plug in a number, you will be taking the absolute value of that number and it will always be positive because a positive times a positive is always a positive, and the absolute value of any multiplication is always a positive also.......
|xy| = sqrt[(xy)^2] = sqrt(x^2 . y^2) = sqrt(x^2) . sqrt(y^2) = |x| |y|

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Ok I am sure someone is going to come up with some elaborate proof and blow this away but...

x = -2
y = 1

l-2*1l = l-2l = 2
l-2l*l1l = 2*1 = 2

So yeah, any time you plug in a number, you will be taking the absolute value of that number and it will always be positive because a positive times a positive is always a positive, and the absolute value of any multiplication is always a positive also.
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