What is the tension in the cable when the man is given an initial upward acceleration of 2.15 m/s2

1) A rescue helicopter is lifting a man (weight = 762 N) from a capsized boat by means of a cable and harness. (a) What is the tension in the cable when the man is given an initial upward acceleration of 2.15 m/s2? (b) What is the tension during the remainder of the rescue when he is pulled upward at a constant velocity?

For this question I would use the "common sense" feel to tell if the cable tension is greater, equal to, or less than the man's weight. In other words, just imagine pulling UP faster than at constant speed. This would put greater tension in the cable than just the man's weight - so the upward acceleration would be *added to* g to create a total acceleration = 9.81 + 2.15 = 11.96 m/s².

The Tension in cable for part (a) = (762/g)(11.96) = 762/9.81(11.96) = 929 N ANS

Part (b) U should know the answer - so I'll let U answer this part :>)