What is the rotational inertia (moment of inertia) of a solid cylinder rotating about the central diameter (see Fig. 2 of lab manual for diagram) if the mass of the cylinder is 8 kg, and the diameter and length are 0.29 m and 0.5 m, respectively?
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R = D/2 = .29/2 = 0.145 m
Icyl = ½mR² = ½*8*0.145² = 0.0841 kg∙m²
Note that the length is not used.....
Icyl = ½mR² = ½*8*0.145² = 0.0841 kg∙m²
Note that the length is not used.....