PartA:How much heat does it take to increase the temperature of 5.00 moles of an ideal monatomic gas from 22.0celsius to 59.0celsius if the gas is held at constant volume? in J
partB: How much heat is needed if the gas is diatomic rather than monatomic? in J
partB: How much heat is needed if the gas is diatomic rather than monatomic? in J
-
we know that heat absorbed = nCv* delta T
here , n = 5 and delta T = 59-22=37..
Part a) for a monoatomic gas gamma=5/3
we know that gamma-1=R/Cv.. so Cv = 3/2R
hence heat required = 5*3/2*37 = 277.5 J
Part B) gamma for diatomic gas equals 7/5
so Cv = 5/2R
hence heat required = 5*5/2*37 = 412.5 J
hope this helps and love you baby..
need +10 points
here , n = 5 and delta T = 59-22=37..
Part a) for a monoatomic gas gamma=5/3
we know that gamma-1=R/Cv.. so Cv = 3/2R
hence heat required = 5*3/2*37 = 277.5 J
Part B) gamma for diatomic gas equals 7/5
so Cv = 5/2R
hence heat required = 5*5/2*37 = 412.5 J
hope this helps and love you baby..
need +10 points