I can't work this out, can anyone show me. Can you include the working so can see how you figured it out? Thanks!
Karim was driving back home to Hamilton from wester Ross, a distance of 250 miles. He stopped half way to phone his wife saying he would be home in 2hours 15minutes. If he averaged 54 miles per hour for the rest of the journey, did he arrive home in time?
Thank you!
Karim was driving back home to Hamilton from wester Ross, a distance of 250 miles. He stopped half way to phone his wife saying he would be home in 2hours 15minutes. If he averaged 54 miles per hour for the rest of the journey, did he arrive home in time?
Thank you!
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He still had 125 miles to go.
This first method uses TIME = DISTANCE/SPEED
If he averaged 54 miles per hour this would take him
125/54 hours = 2 + 17/54 hours = 2 hours and (17*60)/54 minutes = 2 hours 18.88 mins
He would not arrive in time but would be less than 4 minutes late.
This second method use DISTANCE = TIME *SPEED
Another way of calculating is to say that driving 2 hours 15minutes at an average 54 miles per hour he would travel 9/4 *54 miles = 121.5 miles which means that he has not travelled the required 125 miles in the 2 hours 15minutes.
Regards - Ian
This first method uses TIME = DISTANCE/SPEED
If he averaged 54 miles per hour this would take him
125/54 hours = 2 + 17/54 hours = 2 hours and (17*60)/54 minutes = 2 hours 18.88 mins
He would not arrive in time but would be less than 4 minutes late.
This second method use DISTANCE = TIME *SPEED
Another way of calculating is to say that driving 2 hours 15minutes at an average 54 miles per hour he would travel 9/4 *54 miles = 121.5 miles which means that he has not travelled the required 125 miles in the 2 hours 15minutes.
Regards - Ian