Problem: A shipment of 40 TV sets contains 3 defective units. How many ways can a vending company buy five of these units and receive no defects.
I have the answer, but I don't understand how to get the answer. The answer is 37C5=435,897. I don't know what C is and I don't understand how C makes 37 and 5 equal 435,897.
I have the answer, but I don't understand how to get the answer. The answer is 37C5=435,897. I don't know what C is and I don't understand how C makes 37 and 5 equal 435,897.
-
C means combination, or choose
there are 40 sets
3 are defective
40 - 3 = 37 are not defective
37C5 =
37! / [5!(37 - 5)!]
37! / (5! * 32!)
(37 * 36 * 35 * 34 * 33) / (5 * 4 * 3 * 2)
52307640 / 120
435897
different ways
there are 40 sets
3 are defective
40 - 3 = 37 are not defective
37C5 =
37! / [5!(37 - 5)!]
37! / (5! * 32!)
(37 * 36 * 35 * 34 * 33) / (5 * 4 * 3 * 2)
52307640 / 120
435897
different ways