1. The problem statement, all variables and given/known data
Consider a manometer with a glass bulb (Pgas=88kPa) at one end and which is open to the atmosphere (P =101 kPa) at the other. The manometer has two liquids oil and water in it, as shown. If the oil has a density of 823 kg/m3 and water a density of 1.00x103 kg/m3 find the height of the water.
http://s16.postimage.org/9ihj14zir/S...3…
2. Relevant equations
P=pgh
3. The attempt at a solution
I keep deducing the equation to be;
Patm + ρwater*g*H = Pgas + ρoil*g*0.699m
Solving for H, I get 0.750m. The answer though, is 0.269m.
Where am I going wrong?
Consider a manometer with a glass bulb (Pgas=88kPa) at one end and which is open to the atmosphere (P =101 kPa) at the other. The manometer has two liquids oil and water in it, as shown. If the oil has a density of 823 kg/m3 and water a density of 1.00x103 kg/m3 find the height of the water.
http://s16.postimage.org/9ihj14zir/S...3…
2. Relevant equations
P=pgh
3. The attempt at a solution
I keep deducing the equation to be;
Patm + ρwater*g*H = Pgas + ρoil*g*0.699m
Solving for H, I get 0.750m. The answer though, is 0.269m.
Where am I going wrong?
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The question/diagram is wrong: the pressure in the bulb plus the pressure under 0.699m of oil is:
88,000 + (823 x 9.81 x 0.699)
= 93643 Pa
This is LESS than atmospheric pressure.
88,000 + (823 x 9.81 x 0.699)
= 93643 Pa
This is LESS than atmospheric pressure.
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