A block of mass M1 travels from right to left horizontally with a constant speed vo on a plateau of height H until it comes to a cliff. A toboggan of mass M2 is
positioned on level ground below the cliff. The center of the toboggan is a distance D ( left ) from the base of the cliff.
a. Determine D in terms of vo, H, and g so that the block lands in the center of the toboggan.
b. The block sticks to the toboggan which is free to slide without friction. Determine the resulting velocity of the block and toboggan.
positioned on level ground below the cliff. The center of the toboggan is a distance D ( left ) from the base of the cliff.
a. Determine D in terms of vo, H, and g so that the block lands in the center of the toboggan.
b. The block sticks to the toboggan which is free to slide without friction. Determine the resulting velocity of the block and toboggan.
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The time to fall vertically is found using s = ½ at^2
Hence, t =√ (2H/g)
The horizontal distance traveled D = V0 *t
D = V0 √ (2H/g)
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Using conservation of momentum
M1V0 = (M1 + M2) V
Hence
V= M1V0 /( M1 + M2)
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Hence, t =√ (2H/g)
The horizontal distance traveled D = V0 *t
D = V0 √ (2H/g)
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Using conservation of momentum
M1V0 = (M1 + M2) V
Hence
V= M1V0 /( M1 + M2)
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