A car travels 90. meters due north in 15 seconds. Then the car turns around and travels 40. meters due south in 5.0 seconds. What is the magnitude of the average speed of the car during this 20 seconds interval? What is the magnitude of the average velocity of this car during the same 20 seconds interval?
really do not understand this. Help with a example and answer? thank you
really do not understand this. Help with a example and answer? thank you
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The basic formula is d=rt, distance = rate x time. To get the average speed, you use the total distance traveled:
130 = r * 20
r =130 / 20 = 6.5 meters/second
To get the average velocity, you are concerned with distance and direction, from the start to the end of the motion. The net motion is only 50 feet north from the original position:
50 = r * 20
r = 50 / 20 = 2.5 meters/second (north)
130 = r * 20
r =130 / 20 = 6.5 meters/second
To get the average velocity, you are concerned with distance and direction, from the start to the end of the motion. The net motion is only 50 feet north from the original position:
50 = r * 20
r = 50 / 20 = 2.5 meters/second (north)