an engine rotating at 2000rpm has a flywheel of 15kg and a radius of gyration of 300mm attached to a smooth out engine cycle.
what energy is available from the flywheel at this speed in joules?
thanks.
what energy is available from the flywheel at this speed in joules?
thanks.
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E = ½I*w²
I = m*R² = 15*.3² = 1.35 kg∙m²
w = 2000*2π/60 = 209.44 rad/sec
E = ½*1.35*209.44² = 29609 J
I = m*R² = 15*.3² = 1.35 kg∙m²
w = 2000*2π/60 = 209.44 rad/sec
E = ½*1.35*209.44² = 29609 J