Energy in the flywheel question
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Energy in the flywheel question

[From: ] [author: ] [Date: 11-08-14] [Hit: ]
thanks.I = m*R² = 15*.3² = 1.w = 2000*2π/60 = 209.E = ½*1.35*209.......
an engine rotating at 2000rpm has a flywheel of 15kg and a radius of gyration of 300mm attached to a smooth out engine cycle.

what energy is available from the flywheel at this speed in joules?

thanks.

-
E = ½I*w²

I = m*R² = 15*.3² = 1.35 kg∙m²
w = 2000*2π/60 = 209.44 rad/sec

E = ½*1.35*209.44² = 29609 J
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