I know that I'm supposed to use 1/2mg = GmM (R+h)^2 for the first part, solve for h.
what's the difference between m and M in this equation that the teacher gave another student?
a different student said to use this equation: 1/2 g = GM/r^ and doesn't seem to solve for height at all. so confused. and then i got lost when i did the square root thing later. nothing adds up. maybe i'm not using my calc right. The answer is about 2600km. please help.
given info:
G = 6.67x10-11
Massearth = 5.97x10^24
Radiusearth = 6378km
what's the difference between m and M in this equation that the teacher gave another student?
a different student said to use this equation: 1/2 g = GM/r^ and doesn't seem to solve for height at all. so confused. and then i got lost when i did the square root thing later. nothing adds up. maybe i'm not using my calc right. The answer is about 2600km. please help.
given info:
G = 6.67x10-11
Massearth = 5.97x10^24
Radiusearth = 6378km
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An less complicated way to think about and solve this problem is to know that by the Universal gravitational formula:
The Force of gravity is INVERSELY proportional to the SQUARE of distance = 1/d²
so
if the distance beomes √2 then 1/d² = 1/2
In the earth's case d = radius of the earth
so the distance that would halve the Force of gravity would be √2 x radius of earth ANS
The Force of gravity is INVERSELY proportional to the SQUARE of distance = 1/d²
so
if the distance beomes √2 then 1/d² = 1/2
In the earth's case d = radius of the earth
so the distance that would halve the Force of gravity would be √2 x radius of earth ANS