A question on the final review:
A .4 kg mass is attached to a vertical spring and held such that the spring is neither stretched nor compressed. The mass is then allowed to drop. It falls 20 cm below its release position and starts simple harmonic oscillations. If the spring constant is 100N/m, find the period of these oscillations.
OK I have attempted the problem and I start with:
K=100 N/m
m=.4kg
dx=.20m
And the equation T=2pi(x)sqrt(m/K)
plugging in the numbers I get
T=2pi(.20m)*sqrt(.4Kg/100 N/m)
T=.0794767
Is this the correct way to find the period?If not what equations are used?
A .4 kg mass is attached to a vertical spring and held such that the spring is neither stretched nor compressed. The mass is then allowed to drop. It falls 20 cm below its release position and starts simple harmonic oscillations. If the spring constant is 100N/m, find the period of these oscillations.
OK I have attempted the problem and I start with:
K=100 N/m
m=.4kg
dx=.20m
And the equation T=2pi(x)sqrt(m/K)
plugging in the numbers I get
T=2pi(.20m)*sqrt(.4Kg/100 N/m)
T=.0794767
Is this the correct way to find the period?If not what equations are used?
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The correct formula is
T = 2π√[m/k]
The amplitude (x) is not in the formula. It will have the same period regardless of the value of the amplitude.
Tricky stuff, this SHM......
T = 2π√[m/k]
The amplitude (x) is not in the formula. It will have the same period regardless of the value of the amplitude.
Tricky stuff, this SHM......