What is the magnitude of the force per meter of length on a straight wire carrying an 8.40-A current when perpendicualr to a .90-T uniform magnetic field? What if the angle between the wire and field is 45 degrees?
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Magnetic force per unit length = B*I*sin(theta)
When perpendicular, force per unit length = B*I*sin(90) = B*I = 0.9T*8.40A = 7.56 N/m
At 45 deg, force per unit length = B*I*sin(45) = 0.9T*8.40A*0.707 = 5.35 N/m
When perpendicular, force per unit length = B*I*sin(90) = B*I = 0.9T*8.40A = 7.56 N/m
At 45 deg, force per unit length = B*I*sin(45) = 0.9T*8.40A*0.707 = 5.35 N/m