Physics, Force on Electric Current in Magnetic Field.
Favorites|Homepage
Subscriptions | sitemap
HOME > Physics > Physics, Force on Electric Current in Magnetic Field.

Physics, Force on Electric Current in Magnetic Field.

[From: ] [author: ] [Date: 11-05-06] [Hit: ]
force per unit length = B*I*sin(90) = B*I = 0.9T*8.40A = 7.At 45 deg, force per unit length = B*I*sin(45) = 0.9T*8.......
What is the magnitude of the force per meter of length on a straight wire carrying an 8.40-A current when perpendicualr to a .90-T uniform magnetic field? What if the angle between the wire and field is 45 degrees?

-
Magnetic force per unit length = B*I*sin(theta)

When perpendicular, force per unit length = B*I*sin(90) = B*I = 0.9T*8.40A = 7.56 N/m

At 45 deg, force per unit length = B*I*sin(45) = 0.9T*8.40A*0.707 = 5.35 N/m
1
keywords: Electric,Field,Magnetic,Physics,in,Force,Current,on,Physics, Force on Electric Current in Magnetic Field.
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .