I'm sorry. I ask a lot of physics questions on here and trust me, I regret taking the class 'cause my mind doesn't work that kind of logic.
A charged insulating ball of mass 7.0 g with a uniform charge of 1.5*10^-6, hangs from a light thread inclined at an angle of 8.0 degrees to the vertical. Calculate the magnitude of the electric field. Thank you so much:)
A charged insulating ball of mass 7.0 g with a uniform charge of 1.5*10^-6, hangs from a light thread inclined at an angle of 8.0 degrees to the vertical. Calculate the magnitude of the electric field. Thank you so much:)
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The tension T in the thread holding the ball in position is providing two forces on the ball ..
• a vertical component - part that holds the ball up against gravity, Fv = mg
• a horizontal component - part that holds the ball against the horizontal electric force,
Fh = qE .. [C*N/C = N]
A vector diagram of these two components has the relationship ..
tan 8º = Fh/Fv
Fh = Fv.tan 8º = mg.tan 8º
Fh = (7.0E-3kg)(9.80N/kg)(0.1405) = 9.64E-3 N
Electric field E (N/C) = Fh/q .... .. = 9.64E-3 N / 1.50E-6 C .... ►E = 6.43E3 N/C
hope that wasn't too bad for you ..
• a vertical component - part that holds the ball up against gravity, Fv = mg
• a horizontal component - part that holds the ball against the horizontal electric force,
Fh = qE .. [C*N/C = N]
A vector diagram of these two components has the relationship ..
tan 8º = Fh/Fv
Fh = Fv.tan 8º = mg.tan 8º
Fh = (7.0E-3kg)(9.80N/kg)(0.1405) = 9.64E-3 N
Electric field E (N/C) = Fh/q .... .. = 9.64E-3 N / 1.50E-6 C .... ►E = 6.43E3 N/C
hope that wasn't too bad for you ..