what mass of water vapor forms if 28.6g of propane is burned?
a) what is the balanced equation
b) stoichiometric calculations
a) what is the balanced equation
b) stoichiometric calculations
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C3H8+5O2-->3CO2+4H2O
M(C3H8)=44g/mol
28.6/44=0.65mol
1:4=0.65:x
x=2.6mol H2O
2.6mol*M(H2O)=2.6*18=46.8g
m(H2O)=46.8g
M(C3H8)=44g/mol
28.6/44=0.65mol
1:4=0.65:x
x=2.6mol H2O
2.6mol*M(H2O)=2.6*18=46.8g
m(H2O)=46.8g