I don't understand stoichiometric calculation Help please

when 84.8g of solid iron(III) oxide reacts with gaseous carbon monoxide what mass of solid iron is produced?

I don't get how to do stoichiometric. Is there a simple way to do the calculations?
What is the balanced equation?

Fe2O3 + 3 CO → 2 Fe + 3 CO2

(84.8 g Fe2O3) / (159.6887 g Fe2O3/mol) x (2/1) x (55.8452 g Fe/mol) = 59.3 g Fe