What volume of 0.125M H2SO4 is required to neutralize 2.50g of Ca(OH)2

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What volume of 0.125M H2SO4 is required to neutralize 2.50g of Ca(OH)2

[From: ] [author: ] [Date: 11-05-05] [Hit: ]

Step-by-step problem solving would be greatly appreciated, thank you.

H2SO4 + Ca(OH)2 → CaSO4 + 2 H2O

(2.50 g Ca(OH)2) / (74.0932 g/mol) x (1/1) / (0.125 mol/L) = 0.270 L

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