Math help just 2 questions

1.) Identify the vertical asymptote of y = 3/x +2

x = 2
x = –2
y = 0
There is no vertical asymptote.
3.) Identify the vertical and horizontal asymptotes of y = 1/x - 2 - 3.
x = 2; y = –3
x = –2, y = 3
x = 3, y = –2
There are no asymptotes.

1. y = 0

3. As stated, this reduces to y = 1/x - 5
It has a veritcal asymptote at x = 0, and a horizontal asymptote at y = -5

Did you mean y = 1/(x - 2) - 3 ?
That has a verical asymptote at x = 2, and a horizontal asymptote at y = -3

1. The vertical asymptotes of y = 3/x + 2 is x = 0. When x is zero, the fraction 3/x become 3/0 and is therefore undefined so their will be an asymptote here.

2. In the same way the vertical asymptote of y = 1/(x-2) - 3 is x = 2 as when x is 2 then the fraction 1/(x-2) becomes 1/0 and is again undefined. The horizontal asymptote is y = -3, this is because when y is -3 then 1/(x-2) is zero and this is obviously not possible.

I hope this helped!!