Hi.
I am really bad at maths like terrible and i really need some help with my maths homework
basically we have to solve simultaneous equations... and i really don't understand how it works
here are the questions and could you write out how you did it like the method please so i can see how you worked each question.
1) 2x-y=6
4x+3y+22
2) x+5y=8
3x+2y=11
3) 4x+2y=8
x+3y=2
4) 3x+2y=7
5x+4y=12
5) 7x+3y=16
2x+9y=29
6) 4x+2x+10
7x+3y=16
7) 5x+3y=6
7x+4y=9
8) 5x+3y=12
6x-4y=22
Thank you very much your answers are greatly appreciated xx
I am really bad at maths like terrible and i really need some help with my maths homework
basically we have to solve simultaneous equations... and i really don't understand how it works
here are the questions and could you write out how you did it like the method please so i can see how you worked each question.
1) 2x-y=6
4x+3y+22
2) x+5y=8
3x+2y=11
3) 4x+2y=8
x+3y=2
4) 3x+2y=7
5x+4y=12
5) 7x+3y=16
2x+9y=29
6) 4x+2x+10
7x+3y=16
7) 5x+3y=6
7x+4y=9
8) 5x+3y=12
6x-4y=22
Thank you very much your answers are greatly appreciated xx
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This is way too many for me to answer for you, but I'll do the second one so you understand how it's done (you messed up the first one).
x + 5y = 8
3x + 2y = 11
First, choose one of the equations to solve for any variable. I'll pick the first, and solve for x.
x + 5y = 8
x = 8 - 5y
Nothing but simple algebra so far.
Since these equations are "simultaneous", the x's and y's refer to each other. In other words, the x and y in both equations are the same numbers. Now that I know what x is, I can put that in for x in the OTHER equation:
x = 8 - 5y
AND
3x + 2y = 11
SO
3(8 - 5y) + 2y = 11
Simplify by distributing, etc:
24 - 15y + 2y = 11
24 - 13y = 11
And now we can solve for y.
24 = 11 + 13y
13 = 13y
y = 1
And now, since we know y, we can use that in either equation to find x. I'll use the first one again.
x + 5y = 8
x + 5(1) = 8
x + 5 = 8
x = 3
So now we know:
x = 3
y = 1
Good luck!
x + 5y = 8
3x + 2y = 11
First, choose one of the equations to solve for any variable. I'll pick the first, and solve for x.
x + 5y = 8
x = 8 - 5y
Nothing but simple algebra so far.
Since these equations are "simultaneous", the x's and y's refer to each other. In other words, the x and y in both equations are the same numbers. Now that I know what x is, I can put that in for x in the OTHER equation:
x = 8 - 5y
AND
3x + 2y = 11
SO
3(8 - 5y) + 2y = 11
Simplify by distributing, etc:
24 - 15y + 2y = 11
24 - 13y = 11
And now we can solve for y.
24 = 11 + 13y
13 = 13y
y = 1
And now, since we know y, we can use that in either equation to find x. I'll use the first one again.
x + 5y = 8
x + 5(1) = 8
x + 5 = 8
x = 3
So now we know:
x = 3
y = 1
Good luck!
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A teacher of mine gave me a phrase to always remember when dealing with algebra, "Please Excuse My Dear Aunt Sally" meaning the priority to solve the problem,
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