Do you think you can answer this

A 40 g block of ice is cooled to -72°C and is then added to 560 g of water in an 80 g copper calorimeter at a temperature of 23°C. Determine the final temperature of the system consisting of the ice, water, and calorimeter. Remember that the ice must first warm to 0°C, melt, and then continue warming as water. The specific heat of ice is 0.500 cal/g ·°C = 2090 J/kg°C

I have tried the last thirty minutes, can not seem to get the correct answer. Please help me!

You need to specify the specific heat of copper to solve the problem.

The heat gained by the ice going from -72 deg C to 0 deg c + the heat of fusion of the ice + the heat to raise the melted ice to the final temperature from 0 deg C = heat lost by the copper calorimeter + the heat lost by 560 g water from 23 deg C to the final temperature.