Physics, energy and mass problems
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Physics, energy and mass problems

[From: ] [author: ] [Date: 11-05-05] [Hit: ]
or if they want me to break it down into what it would weigh as just protons and neutrons or what.-Well 1 atom of U235 releases3.and 2000 TWh = 7.so you would need 7.2 × 10^18 /3.244 × 10^−11 =2.......
Nuclear-energy production worldwide was 2.0x10^3 TW*h in 1993. What mass of U-235 releases an equivalent amount of energy in the form of binding energy?

U-235 is 235.043934 Amu per atom

Please explain this to me, I can't figure out what they are asking, or if they want me to break it down into what it would weigh as just protons and neutrons or what.

-
Well 1 atom of U235 releases 3.244 × 10^−11 J of when fissioned
and 2000 TWh = 7.2 × 10^18 J

so you would need 7.2 × 10^18 /3.244 × 10^−11 =2.22× 10^29 atoms of uranium 235
Avogadro's Constant is 6.02× 10^23. So 2.22× 10^29 is 370000 moles of uranium235.
which would weigh 87 000 000g or 87 tonnes

So my answer is that you would need 87 tonnes of U235 to supply the worlds nuclear power plants.

About 500 tonnes of U235 are mined each year.
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