More Physics. Please Help.

Refer your answer to the questions on the problem below.
Vector A, of magnitude 5.0 cm, is at 36.9° counter clockwise from the +x – axis. It is added to vector B, and the resultant is vector of magnitude 5.0 cm, at 53.1° counter clockwise from the +x-axis.

The angle between the resultant vector and vector A is?
What is the magnitude of the sum of two vectors?
What is the angle between two given vectors?
What is the angle of vector B from counter clockwise of –x – axis?

Refer your answer to the questions on the problem below.

Given that: A = -2i + 5j and B = 3i - j

Find the magnitude of Vector A.
Find the magnitude of Vector B.
The magnitude of the scalar product vectors A•B is?
The angle between the two vectors A and B is?
Find the angle α of vector A?
Find the angle α of vector B?
What is the magnitude of Σx in the product of A x B?
What is the magnitude of Σy in the product of A x B?
What is the magnitude of Σz in the product of A x B?
What is the magnitude of the product of A x B?

Refer your answer to the questions on the problem below.
Vector A, of magnitude 5.0 cm, is at 36.9° counter clockwise from the +x – axis. It is added to vector B, and the resultant is vector of magnitude 5.0 cm, at 53.1° counter clockwise from the +x-axis.

Angle between Resultant and A = 53.1 – 36.9 = 16.2°
Ax = 5 * cos 36.9 =
Ay = 5 * sin 36.9
These are the coordinates of the end point of Vector A

Rx = 5 * cos 53.1
Ry = 5 * sin 53.1
These are the coordinates of the end point of Vector R

Vector B goes from the end point of Vector A to the end point of Vector R.

∆x = 5 * cos 53.1 – 5 * cos 36.9 = 5 * (cos 53.1 – cos 36.9)
∆y = 5 * sin 53.1 – 5 * sin 36.9 = 5 * (sin 53.1 – sin 36.9)


Length of Vector B = [(∆x)^2 + (∆y)^2]^0.5
5 * [(cos 53.1 – cos 36.9)^2 + (sin 53.1 – sin 36.9)^2]^05 = 1.409


tangent of angle = ∆y ÷ ∆x = -1