A snorkeler with a lung capacity of 6.4L inhales a lungful of air at the surface, where the pressure is 1.0atm. The snorkeler then descends to a depth of 22m, where the pressure increases to 3.2atm.
What is the volume of the snorkeler's lungs at this depth? (Assume constant temperature.)
Express your answer using two significant figures.
V2=___________L
What is the volume of the snorkeler's lungs at this depth? (Assume constant temperature.)
Express your answer using two significant figures.
V2=___________L
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6.4 * 1/3.2 = 2.0L
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P1V1 = P2V2
1 atm * 6.4L = 3.2 atm * "X" liters
solve for X:
X = V2 = 1 atm * 6.4 / 3.2 atm
V2 = 2 Liters
1 atm * 6.4L = 3.2 atm * "X" liters
solve for X:
X = V2 = 1 atm * 6.4 / 3.2 atm
V2 = 2 Liters