Can anyone help me work out these indice equations? :)
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Can anyone help me work out these indice equations? :)

[From: ] [author: ] [Date: 11-04-28] [Hit: ]
......
(i) 27 1/3

(ii) 64 -2/3

(iii) 4 (cubed root of) 2 = 2 n/3

Would be much appreciated! Thanks :D

-
Hi Clo

(i)
27^1/3 = 3

(ii)
64^-2/3 = 1/16

(iii)
4 (cubed root of) 2 = 2^n/3
2^2 * 2^1/3 = 2^n/3
2^(2 +1/3) = 2^n/3
2^7/3 = 2^n/3
n = 7

Shy
1
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