An object is placed 5.50 cm in front of a converging lens with a focal length equal to 5.00 cm. a.)What is the position of the image? b.) Is the image real or virtual? c.) Is the image upright or inverted? d.) If the height of the object is 2.00 cm, what is the height of the image?
I tried this but got a really big answer for a.) so I don't think I did it right :(
I tried this but got a really big answer for a.) so I don't think I did it right :(
-
The object is very close to the focal length so you should get a big answer for a :)
a)
1/f = 1/do + 1/di
f = 5.00 cm
do = 5.50 cm
Solve for di
di = 55.0 cm (on the opposite side of the lens as the object)
b)
real
c)
inverted
d)
Magnification equation:
M = -di/do = hi/ho
ho = 2.00 cm
You know di and do
Solve for hi
hi = -20.0 cm (negative just means that it is inverted)
a)
1/f = 1/do + 1/di
f = 5.00 cm
do = 5.50 cm
Solve for di
di = 55.0 cm (on the opposite side of the lens as the object)
b)
real
c)
inverted
d)
Magnification equation:
M = -di/do = hi/ho
ho = 2.00 cm
You know di and do
Solve for hi
hi = -20.0 cm (negative just means that it is inverted)