Or by quadratic formula:
2x^2 -27x +70 = 0 when x = (27 +/- sqrt(27^2 - 8*70)) / 4
x = (27 +/- 13) / 4
x = 10 or 7/2
2x^2 -27x +70 = (x - 10)(2x - 7)
-
germano say: Hello,
2x² - 27x + 70 =
let's split - 27x into - 20x - 7x:
2x² - 20x - 7x + 70 =
let's group terms as:
(2x² - 20x) - (7x - 70) =
let's factor 2x out of the first binomial and 7 out of the second one, yielding the common factor (x - 10):
2x (x - 10) - 7(x - 10) =
finally let's factor out (x - 10), ending with:
(x - 10)(2x - 7)
I hope it helps
-
Rogue say: when factoring ax^2 + bx + c, find the factors of the product ac that sum to b and use them factor via grouping.
2x^2 − 27x + 70
ac = 2 * 70 = 140
-20 * -7 = 140
-20 + -7 = -27 = b
∴ 2x^2 − 20x − 7x + 70
∴ 2x(x − 10) − 7(x − 10)
∴ (x − 10)(2x − 7)
-
Jim Moor say: (2 x - 7) (x - 10)
-
Kara say: well,
2x^2 -27x +70 = (2 x - 7)(x - 10)
hope it' ll help !!
-
bruce 888 say: Q. 2x^2 -27x +70
=> ( 2x )( x ) - ( 7 + ( 10 x 2) )( x ) + ( 7 )( 10 ) ( factorize the terms )
=> ( 2x -7 ) ( x - 10 )
-
Valerie say: by factors:
2 * 70 = 140
find a pair of factors of 140 whose sum is -27...
answer is -7 and -20
2x^2 -27x +70 = 2x^2 -7x - 20x +70
= x(2x - 7) - 10(2x - 7)
= (2x - 7)(x - 10)
or by quadratic formula:
2x^2 -27x +70 = 0 when x = (27 +/- sqrt(27^2 - 8*70)) / 4
x = (27 +/- 13) / 4
x = 10 or 7/2
2x^2 -27x +70 = (x - 10)(2x - 7)
-
Michael say: Well,
2x^2 -27x +70 = (2 x - 7)(x - 10)
hope it' ll help !!
-
Philip say: f(x) = 2x^2 -27x +70. Put f(x) = 0. Then 4x = 27(+/-)D, where D^2 = (27)^2 - 4*2*70 = 729 - 560 =
169 = (13)^2. Then D = 13 and x = (1/4)[27(+/-)13] = (1/4)[14 or 40] = (7/2) or 10. Put g(x) =
(x - 7/2)(x - 10). Then 2g(x) = (2x-7)(x-10) = 2x^2 -7x -20x +70 = 2x^2 -27x +70 = f(x).
-