Ok I'm dumb. I have this equation,
log (a) = b+ constant. Otherwise written as log (a) = b+c What does 'a' equal to? I know that it'd be a=e^b but there's a constant here. Thanks for your help!
log (a) = b+ constant. Otherwise written as log (a) = b+c What does 'a' equal to? I know that it'd be a=e^b but there's a constant here. Thanks for your help!
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Well Juan is assuming that the base is 10, which is understandable. You should have specified your base.
But he is right;
For any base a = (base value)^(b+c)
But he is right;
For any base a = (base value)^(b+c)
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log(a) = b + c
10^log(a) = 10^(b + c)
a = 10^(b + c)
10^log(a) = 10^(b + c)
a = 10^(b + c)
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let log(a) = b+c
or, a = e^(b+c)
or, a = e^b *e^c
or, a = e^(b+c)
or, a = e^b *e^c
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log is used to denote log to the base 10 and ln is used to note ln to the base e. Thus
log(a) = b+c means; a = 10^(b+c)
log(a) = b+c means; a = 10^(b+c)