Water flowing through a pipe suddenly comes to a section of pipe where the pipe
diameter decreases to 86% of its previous value. If the speed of the water in the
larger section of the pipe was 32 m/s, what is its speed in this smaller section?
Could some SHOW me how to find the answer??
diameter decreases to 86% of its previous value. If the speed of the water in the
larger section of the pipe was 32 m/s, what is its speed in this smaller section?
Could some SHOW me how to find the answer??
-
Let's say the larger pipe is 1m. diameter. That makes the smaller 0.86m. diameter.
(32 x 1^2)/(0.86^2) = 43.2666m/sec. approx.
Pipe area = (pi r^2).
Because pi is common to both area measurements, you can forget it, as it cancels itself. You just use the squares of either dia. or radius, either works.
(32 x 1^2)/(0.86^2) = 43.2666m/sec. approx.
Pipe area = (pi r^2).
Because pi is common to both area measurements, you can forget it, as it cancels itself. You just use the squares of either dia. or radius, either works.
-
The same amount amount must flow in each section so the speed times the cross-section remains constant. Thus, the speed becomes 32*/(0.86^2)=48.7 m/s