A private school reduces the discounted monthly tuition cost of $285 by $12 per child if a family has more than one child attending the school. Write an algebraic expression that gives the monthly tuition cost per child for a family having c children. (Assume c > 1.)
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285 - 12c
(92 - x)/3
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(92 - x)/3
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> please,Translate the phrase to an algebraic expression. (Use x for the number.)
"the difference of a number and 92 " translates to (x - 92)
"one-third of the difference of a number and 92 " translates to (1/3)(x - 92)
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A private school reduces the discounted monthly tuition cost of $285 by $12 per child if a family has more than one child attending the school. Write an algebraic expression that gives the monthly tuition cost per child for a family having c children. (Assume c > 1.)
Tuition for
1st child = 285
2nd child = (285-12) = 273
3rd child = (285-12) = 273
:
child#c = (285-12) = 273
the total monthly tuition cost (T) for a family having c children (c>1) is
T(c) = 285 + 273(c-1)
the monthly tuition cost (T) PER CHILD for a family having c children (c > 1) is
T(c) = [285 + 273(c-1)]/c
"the difference of a number and 92 " translates to (x - 92)
"one-third of the difference of a number and 92 " translates to (1/3)(x - 92)
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A private school reduces the discounted monthly tuition cost of $285 by $12 per child if a family has more than one child attending the school. Write an algebraic expression that gives the monthly tuition cost per child for a family having c children. (Assume c > 1.)
Tuition for
1st child = 285
2nd child = (285-12) = 273
3rd child = (285-12) = 273
:
child#c = (285-12) = 273
the total monthly tuition cost (T) for a family having c children (c>1) is
T(c) = 285 + 273(c-1)
the monthly tuition cost (T) PER CHILD for a family having c children (c > 1) is
T(c) = [285 + 273(c-1)]/c
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mtc = 285 -.12(285)
(x-92)/3
(x-92)/3
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on your second question is that number greater than 92,because it could either be x-92 or 92-x