x^2 -2xy-4x-3y^2
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x^2 -2xy-4x-3y^2= 0 => the equation of hyperbola, rewrite as:
x^2 -(2y + 4)x - 3y^2 = 0
using the quadratic formula:
ax² + bx + c = 0
x = [– b ± √(b² – 4ac)] / 2a
in this case: a = 1 , b = -(2y + 4) , c = -3y^2
plug in for a, b & c and solve:
x = [(2y + 4) ± √(4y^2 + 16y + 16 + 12y^2)] / 2
x = [2(y + 2) ± 4√(y^2 + y + 1)] / 2
x = y + 2 ± 2√(y^2 + y + 1)
I hope this helps.
x^2 -(2y + 4)x - 3y^2 = 0
using the quadratic formula:
ax² + bx + c = 0
x = [– b ± √(b² – 4ac)] / 2a
in this case: a = 1 , b = -(2y + 4) , c = -3y^2
plug in for a, b & c and solve:
x = [(2y + 4) ± √(4y^2 + 16y + 16 + 12y^2)] / 2
x = [2(y + 2) ± 4√(y^2 + y + 1)] / 2
x = y + 2 ± 2√(y^2 + y + 1)
I hope this helps.
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This is not an equation. So it cannot be solved. An equation has 2 sides -- RHS (right hand side), LHS (left hand side) and an equal sign.
Please type the complete problem
Please type the complete problem