I've been trying to make sense of this for a while now but I just dont get it, I would really appreciate anyone who can help me!
This is the problem:
Suppose you are going to roll a 6 sided dice 60 times and record p, the proportion of times that a 1 or 2 is showing. What value should the sampling distribution of p be centered around? Explain your answer.
I will give 5 stars to whoever can help me, thanks a lot!!
This is the problem:
Suppose you are going to roll a 6 sided dice 60 times and record p, the proportion of times that a 1 or 2 is showing. What value should the sampling distribution of p be centered around? Explain your answer.
I will give 5 stars to whoever can help me, thanks a lot!!
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Let p-hat be the proportion of 2 or 3 in 60 rolls.
Probability of 2 or a 3 = 2/6 = 1/3
Expected value of p-hat = 1/3
Variance of p-hat = p(1-p)/n = [(1/3)(2/3)]/60 =1/270
p-hat is normally distributed with mean 1/3 and variance = 1/270
Probability of 2 or a 3 = 2/6 = 1/3
Expected value of p-hat = 1/3
Variance of p-hat = p(1-p)/n = [(1/3)(2/3)]/60 =1/270
p-hat is normally distributed with mean 1/3 and variance = 1/270