Help me solve for x (logs)

log3 (2x-1) + log3 (x=7) = 3

log_3 ((2x-1)*(x+7)) = 3

exponentiate both sides by 3:

(2x-1)(x+7) = 3^3

2x^2 - x + 14x - 7 = 27

2x^2 + 13x -34 = 0

2x^2 - 4x + 17x - 34 = 0

2x(x-2) + 17(x-2) = 0

(2x+17)(x-2) = 0

x-2 = 0
so x = 2

or
2x+17 = 0
so x = -17/2

x = 2, -17/2