solve the system below graphically. indicate the method you used to plot the lines. Show all your work.
x=2y
2x+y=-5
Check by substituting the answer back into the original equations
x=2y
2x+y=-5
Check by substituting the answer back into the original equations
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2(2y)+y=-5
4y+y=-5
5y=-5
y=-1
x=2y
x=2(-1)
x=-2
The point on the graph you are looking for is (-2,-1)
y=-2x-5
4y+y=-5
5y=-5
y=-1
x=2y
x=2(-1)
x=-2
The point on the graph you are looking for is (-2,-1)
y=-2x-5
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It says to solve graphically, so you graph each line and find the point where they intersect. Plot at least two points and draw the line through them.
methods for graphing lines (they tell you to indicate your method):
-- equation in "y=mx+b" form; m=slope and b=y-intercept(y)
Plot a point at (0, b) (y-intercept). From there, use the slope ("rise over run") to get another point. Draw the line through the points.
-- intercepts: Determine the x- and y-intercepts, algebraically; for each one, make the other variable 0 in the equation, and solve the equation. Plot the intercepts and draw the line through them.
methods for graphing lines (they tell you to indicate your method):
-- equation in "y=mx+b" form; m=slope and b=y-intercept(y)
Plot a point at (0, b) (y-intercept). From there, use the slope ("rise over run") to get another point. Draw the line through the points.
-- intercepts: Determine the x- and y-intercepts, algebraically; for each one, make the other variable 0 in the equation, and solve the equation. Plot the intercepts and draw the line through them.
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x=2y so you plug in 2y for x in the 2x+y=5 equation. You get 2(2y) + y=5 which is 5y=5; divide by 5 on each side to get y=1. Next plug in 1 in either equation to solve for x. So x=2y, since y=1, x=2(1), x=2.
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Maybe this will help http://www.algebra.com/algebra/homework/Graphs/Graphs.faq.question.503318.html Hope it helps :)
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y=-1, x = 2
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If you are substituting than it would be 2x+(2y)=.5 than subtract 2x so it would be 2y=-2x+.5
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x=0
y=0
y=0