For each of the unbalanced equations, calculate how many moles of the second reactant would be required to to react completely with exactly 25.0g of the first reactant. Indicate clearly the mole ratio used for each conversion.
a.) Mg(s) + CuCl2(aq) ---- MgCl2(aq) + Cu(s)
b.) AgNO3(aq) + NiCl2(aq) ---- AqCl(s) + Ni(NO3)2(aq)
c.) NaHSO3(aq) + NaOH(aq) ---- Na2SO3(aq) +H2O(l)
a.) Mg(s) + CuCl2(aq) ---- MgCl2(aq) + Cu(s)
b.) AgNO3(aq) + NiCl2(aq) ---- AqCl(s) + Ni(NO3)2(aq)
c.) NaHSO3(aq) + NaOH(aq) ---- Na2SO3(aq) +H2O(l)
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a.)
Mg + CuCl2 → MgCl2 + Cu
(25 g Mg) / (24.30506 g Mg/mol) x (1 mol CuCl2 / 1 mol Mg) x
(134.4527 g CuCl2/mol) = 138 g CuCl2
b.)
2 AgNO3 + NiCl2 → 2 AgCl + Ni(NO3)2
(25 g AgNO3) / (169.873 g AgNO3/mol) x (1 mol NiCl2 / 2 mol AgNO3) x
(129.5998 g NiCl2/mol) = 9.5 g NiCl2
c.)
NaHSO3 + NaOH → Na2SO3 + H2O
(25 g NaHSO3) / (104.0615 g NaHSO3/mol) x (1 mol NaOH / 1 mol NaHSO3) x
(39.99715 g NaOH/mol) = 9.6 g NaOH
Mg + CuCl2 → MgCl2 + Cu
(25 g Mg) / (24.30506 g Mg/mol) x (1 mol CuCl2 / 1 mol Mg) x
(134.4527 g CuCl2/mol) = 138 g CuCl2
b.)
2 AgNO3 + NiCl2 → 2 AgCl + Ni(NO3)2
(25 g AgNO3) / (169.873 g AgNO3/mol) x (1 mol NiCl2 / 2 mol AgNO3) x
(129.5998 g NiCl2/mol) = 9.5 g NiCl2
c.)
NaHSO3 + NaOH → Na2SO3 + H2O
(25 g NaHSO3) / (104.0615 g NaHSO3/mol) x (1 mol NaOH / 1 mol NaHSO3) x
(39.99715 g NaOH/mol) = 9.6 g NaOH