How do i solve this right triangle

just need help..learned it in math but don't understand a thing..

b= 4, β= 10 degrees, find a, c and α

thanks

Can I assume that b is the side opposite the angle &beta:? I will further assume that c is the hypotenuse of the right triangle.

then:
b/c = sin(10)
c = b/sin(10) = 4/sin(10) = 23.035

α + β = 90
α = 90 - 10 = 80

We now have multiple ways of solving for the side "a"

a/c = sin(80)
a = c sin(80) = 23.036* sin(80) = 22.685

a/c = cos(10)
a = 23.036*cos(10) = 22.685

a^2 + b^2 = c^2
a^2 = c^2 - b^2 = 23.036^2 - 4^2 = 514.615
a = √514.615 = 22.685

draw it Autumn:

then you 'll see that α must = 80
and that we can use trig functions to find the sides:

sin(10) = 4/c or C = 4/(sin(10)

and a = 4/tan(10) because tan(10) = 4/a

got it?

Assuming that a is the other leg of the right triangle and c is the hypotenuse:
α = 180 - 90 - β

a = 4/tan(10) ≅ 22.685

c = 4/sin(10) ≅ 23.035

here is my answer
http://img542.imageshack.us/img542/9428/…