What is the volume of 1.00 mole of H2SO4 at STP

H2SO4 is a liquid at STP, so PV = nRT won't help you here.

1.00 mole of H2SO4 = 98.1 g

V = Density/mass
V = Density/98.1 g

Look up the density of H2SO4 and substitute it into the equation above, and you'll have your answer.

Use PV=nRT
Solve for V:

V=nRT/P // now just plug all the STP values in:

V = (1 mol)(0.082057 L*atm/mol*K)(273.15K)/1 atm = 22.41 L

22.4 L

according the ideal gas law which then would be 22.4L
but there is not enough information because sulfuric acid is an acid which is usually a aqueous