Question = Find fog
f (x) = lnx
g(x) = e^x √x
ANSWER: x + (lnx / 2)
f (x) = lnx
g(x) = e^x √x
ANSWER: x + (lnx / 2)
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Its called composition of functions. first you operate g and then f
f o g (x) = f (g(x))=f( e^x √x) = ln( e^x √x)=ln(e^x)+ln(√x)
= x + 1/2ln(x) = x + ln(x)/2
f o g (x) = f (g(x))=f( e^x √x) = ln( e^x √x)=ln(e^x)+ln(√x)
= x + 1/2ln(x) = x + ln(x)/2