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antiderivative
wierd f looking sign (x^2+5)^3 dx
the answer is 1/7x^7+3x^5+25x^3+125x+c
HOW DID THEY GET THAT
antiderivative
wierd f looking sign (x^2+5)^3 dx
the answer is 1/7x^7+3x^5+25x^3+125x+c
HOW DID THEY GET THAT
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I feel I've just answered this.
INT (x² + 5)³ dx
INT (x^6 + 15x^4 + 75x² + 125) dx
(1/7)x^7 + 3x^5 + 25x^3 + 125x + c
Notice that (x² + 5)³ = (x^6 + 15x^4 + 75x² + 125), which can be found by expanding the binomial.
INT (x² + 5)³ dx
INT (x^6 + 15x^4 + 75x² + 125) dx
(1/7)x^7 + 3x^5 + 25x^3 + 125x + c
Notice that (x² + 5)³ = (x^6 + 15x^4 + 75x² + 125), which can be found by expanding the binomial.
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http://www.pravoslavie.ru/engl… http://www.youtube.com/watch?v… http://esv.scripturetext.com/r… http://esv.scripturetext.com/r… http://bible.cc/1_john/1-5.htm
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(x^2+5)^3=x^6+15x^4+75x^2+125
if you integrate this you get
1/7x^7+3x^5+25x^3+125x+c
if you integrate this you get
1/7x^7+3x^5+25x^3+125x+c