Suppose we have 40 cards numbered 1 through 40 and we want to pick 6 of them one at a time such that order of picking card “does matter”.
A. probability of numbers 1 and 2 are not among those cards?
B. probability of at least numbers one of numbers 10, 11, 12 are among those cards?
Please correct me
a) P(38,6)/P(40,6)
b) 1- [p(37,6)/p(40,6)]
A. probability of numbers 1 and 2 are not among those cards?
B. probability of at least numbers one of numbers 10, 11, 12 are among those cards?
Please correct me
a) P(38,6)/P(40,6)
b) 1- [p(37,6)/p(40,6)]
-
fine !
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