A main supply pipe of radius 8.1 mm is connected to two pipes A and B of radii 5.71 mm and 3.15 mm respectively. If the speed of the water in the main supply pipe is 7.28 m/s, what is the speed of the water in pipe A, if pipe B is closed (i.e., blocked)?
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Water is considered a incompressible fluid so the volume of water flowing in the main is equal to the volume flowing through the branches. Since branch B is blocked, the volume flowing in branch A is equal to the volume flowing through the main.
Volume = velocity x pi x (radius) ^2 Since volume(main) = volume(branch a) the equation simplifies to:
velocity (main) x (rad-main)^2 / ((rad -A)^2 = 7.28 x 2 =14.56 m/s
Volume = velocity x pi x (radius) ^2 Since volume(main) = volume(branch a) the equation simplifies to:
velocity (main) x (rad-main)^2 / ((rad -A)^2 = 7.28 x 2 =14.56 m/s