Here's the disgram; http://tinypic.com/r/167plj5/6
Starting with an initial speed of 5.00 m/s at a height of 0.300 m, a 1.50 kg ball swings
downward and strikes a 4.60 kg ball that is at rest, as shown. (a) Using the principle of
conservation of mechanical energy, find the speed of the 1.50 kg ball just before
impact.
So, KEi + PEi = KEf + PEf
1/2mv^2 + mgh [initial] = 1/2mv^2 + mgh [final]
The answer is 5.56m/s, but I'm getting something different. Can anyone walk me through the process? I'm not sure where I'm going wrong. Any help is greatly appreciated.
Starting with an initial speed of 5.00 m/s at a height of 0.300 m, a 1.50 kg ball swings
downward and strikes a 4.60 kg ball that is at rest, as shown. (a) Using the principle of
conservation of mechanical energy, find the speed of the 1.50 kg ball just before
impact.
So, KEi + PEi = KEf + PEf
1/2mv^2 + mgh [initial] = 1/2mv^2 + mgh [final]
The answer is 5.56m/s, but I'm getting something different. Can anyone walk me through the process? I'm not sure where I'm going wrong. Any help is greatly appreciated.
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By the law of energy conservation:-
=>[KE+PE]initial = KE(final)
=>1/2mu^2 + mgh = 1/2mv^2
=>v^2 = u^2 + 2gh
=>v^2 = (5)^2 + 2 x 9.8 x 0.3
=>v = √30.88
=>v = 5.56 m/s
=>[KE+PE]initial = KE(final)
=>1/2mu^2 + mgh = 1/2mv^2
=>v^2 = u^2 + 2gh
=>v^2 = (5)^2 + 2 x 9.8 x 0.3
=>v = √30.88
=>v = 5.56 m/s
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v^2 = u^2 + 2gh = 30.88 ---> v = 5.557