Algebra one help homework

Find the equation of yhe line in slope-intercept form that is perpendicular to y=-1/2x + 6 and passes through (3,-1).

Lines that are perpendicular to each other have the negative reciprocal slope, so start off by making the slope 2. Then, plug (3,-1) into your equation. 3 as x, and -1 as y. So you get -1=2(3) + b. Then solve for b, and you get -7. Put your equation together and it's y = 2x - 7. Hope this helps!

The equation of a line is y = mx. That line passes through the origin. If you want it to pass through some point (a, b) then you subtract the coordinates of that point: y - b = m(x - a)

The perpendicular has slope equal to the negative reciprocal. You are given -1/2 so the slope of the perpendicular is 2. Putting it all together:

y + 1 = 2(x - 3) <-- Point-slope form

You can rewrite that in any form you choose.

y = 2x - 4 <-- Slope-intercept form

y - 2x + 4 = 0 <-- Standard form

if it is perpendicular to the line, then the slope will be just the negative of the given slope, so 1/2 instead of -1/2
so use point slope form and transform to slope intercept.
y-(-1) = m(x-3)
y+1 = 1/2x -3/2
y = 1/2x -5/2

Y= 1/2x +?