Let f(x)=8x+(6/x).Find the open intervals on which f is increasing (decreasing)

Let f(x)=8x+(6/x).Find the open intervals on which f is increasing (decreasing).?
I know: it's increasing at: (-infinity,-(sqrt(3))/2), ((sqrt(3))/2, infinity)
I do not know: when it's decreasing. It is not "none" or (-(sqrt(3))/2), ((sqrt(3))/2)
I also know Relative Max:-(sqrt(3))/2)
Relative Min: ((sqrt(3))/2

f(x)=8x+(6/x)

f'(x) = 8 - 6/x²
f'(x) = 0 at x = ±√3/2
f'(x) is undefined at x = 0

f(x) is increasing at intervals (-infinity, -√3/2) U (√3/2, infinity) because f '(x) is positive.
f(x) is decreasing at intervals (-√3/2, 0) U (0, √3/2) because f '(x) is negative.