A spring oriented vertically is attached to a hard horizontal surface as in the figure below. The spring has a force constant of 1.68 kN/m. How much is the spring compressed when a object of mass m = 2.80 kg is placed on top of the spring and the system is at rest?
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I'm a student, so my answer might be incorrect, but this is how I would do it.
F=Kx, where f= force, k=spring constant, and x = the displacement (or distance)
Force = mass x gravity
F= 2.80(9.8) = 27.44 N
K=1.68kN/m
I'm not sure if it's necessary, but I would convert kN/m to N/m, so K = 1680N/m
Now plug in F and K and solve for X.
27.44 N = (1680 N/m)(x)
X=0.0163 meters
F=Kx, where f= force, k=spring constant, and x = the displacement (or distance)
Force = mass x gravity
F= 2.80(9.8) = 27.44 N
K=1.68kN/m
I'm not sure if it's necessary, but I would convert kN/m to N/m, so K = 1680N/m
Now plug in F and K and solve for X.
27.44 N = (1680 N/m)(x)
X=0.0163 meters