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PHYSICS HELP ASAP PLEASE

[From: ] [author: ] [Date: 12-11-20] [Hit: ]
CAN ANYONE SOLVE THIS-In simple harmonic motion(SHM) V(max) = A*w, here w is the angular frequency.a(max) = A*w^2.1.6.Dividing the above equation we have: (6.......
An object attached to a horizontal spring is oscillating back and forth along a frictionless surface. The maximum speed of the object is 1.91 m/s, and its maximum acceleration is 6.11 m/s2. How much time elapses betwen an instant when the object's speed is at a maximum and the next instant when its acceleration is at a maximum?
CAN ANYONE SOLVE THIS

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In simple harmonic motion(SHM) V(max) = A*w, here w is the angular frequency.
a(max) = A*w^2. Substituting numbers:
1.91 = A*w
6.11 = A*w^2
Dividing the above equation we have: (6.11) / (1.91) = (Aw^2) / (Aw) => w = 3.20. Since T = (2 pi)/w =>
T = 1.96 s. It takes a quarter of the period from the maximum speed (central position) to the maximum acceleration ( maximum displacement) therefore the time = T / 4 = 0.49 s
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