log5(x)=3
log3(3x-2)=2
log6(36)=5x+3
e^(2x+5)=8
Thanks!!
log3(3x-2)=2
log6(36)=5x+3
e^(2x+5)=8
Thanks!!
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log₅(x)=3
implies ---> 5³ = x
5³ = 125 = x
log₃(3x-2)=2
implies ---> 3² = 3x-2
✈ 9 = 3x-2
✈ 11 = 3x
✈ x = 11/3 ≈ 3.67
log₆(36)=5x+3
✈ 2 = 5x+3 (Since 6² = 36)
✈ 5x = -1
✈ x = -1/5 = -0.2
e^(2x+5)=8, (Take the natural log of both sides to rid of e)
✈ 2x+5 = ln(8)
✈ x = (ln(8)-5)/2 ≈ -1.46
implies ---> 5³ = x
5³ = 125 = x
log₃(3x-2)=2
implies ---> 3² = 3x-2
✈ 9 = 3x-2
✈ 11 = 3x
✈ x = 11/3 ≈ 3.67
log₆(36)=5x+3
✈ 2 = 5x+3 (Since 6² = 36)
✈ 5x = -1
✈ x = -1/5 = -0.2
e^(2x+5)=8, (Take the natural log of both sides to rid of e)
✈ 2x+5 = ln(8)
✈ x = (ln(8)-5)/2 ≈ -1.46