Use angles of elevation and depression to solve the problem
Two hills are 2 miles apart. The taller hill is 2707 ft high. the angle of depression from the top of the taller hill to the top of the shorter hill is 7 degrees. Find the height of the shorter hill to the nearest foot. (1mi =5280ft)
please explain and show work of how you get the answer i have like 10 more problems of these and i cant figure it out.
Thank you
Two hills are 2 miles apart. The taller hill is 2707 ft high. the angle of depression from the top of the taller hill to the top of the shorter hill is 7 degrees. Find the height of the shorter hill to the nearest foot. (1mi =5280ft)
please explain and show work of how you get the answer i have like 10 more problems of these and i cant figure it out.
Thank you
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Right triangle (draw it out -- hypotenuse is top to top)
base is 2 miles = 10560 feet
theta = 7 degrees
tan(theta) = base/h
where h is the height difference.
or h= base/tan(7deg)
height of shorter hill is taller - difference = 2707 - h
base is 2 miles = 10560 feet
theta = 7 degrees
tan(theta) = base/h
where h is the height difference.
or h= base/tan(7deg)
height of shorter hill is taller - difference = 2707 - h