Need Some Math Help! - Functions
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Need Some Math Help! - Functions

[From: ] [author: ] [Date: 12-11-19] [Hit: ]
then its simply a matter of thinking about how a function works.If its f(x) = 1/x, then if you apply the function to anything else, say f(w), youre going to get 1/w.Thus when you are looking for a* f(k(x-p)) + q,......
This section I'm learning right now is called graphing transformations.

For the following functions, find y = af(k(x-p))+q.

1. f(x) = 1/x
2. f(x) = |x|

Answers:

1) y = (a/k(x - p)) + q
2) y = a|k(x - p)| + q


I don't know the following steps to take to come to the answer? In other words, even though I was given the answer I don't know how to get to the answer.

Any help would greatly be appreciated!

MB

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If you're looking to see how to get the second equation, then it's simply a matter of thinking about how a function works. If it's f(x) = 1/x, then if you apply the function to anything else, say f(w), you're going to get 1/w.

Thus when you are looking for a* f(k(x-p)) + q, you're essentially 'replacing' x with k*(x-p), resulting in the first being 1 / [k*(x-p)] and the second being |k*(x-p)|.

Now the outer portion of those are being applied after the function is evaluated, so you multiply the end result by a and and then add q to it.

Thus giving you:

1) a* 1/[k(x - p)] + q
2) a* |k(x - p)| + q
1
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