log(x+6)=1
3log2(x-1)+log2(4)=5
ln(x+1)-ln(x)=2
Thanks!!
3log2(x-1)+log2(4)=5
ln(x+1)-ln(x)=2
Thanks!!
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i) x+6 = 10
x = 4
ii) log2[4(x-1)^3] = log2 [32]
(x-1)^3 = 8
x-1 = 2
x = 3
iii) ln [(x+1)/x] = 2
(x+1)/x = e^2
x+1 = x*e^2
x(e^2-1) = 1
x = 1/(e^2-1)
x = 4
ii) log2[4(x-1)^3] = log2 [32]
(x-1)^3 = 8
x-1 = 2
x = 3
iii) ln [(x+1)/x] = 2
(x+1)/x = e^2
x+1 = x*e^2
x(e^2-1) = 1
x = 1/(e^2-1)
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1)x=4
2)x=3
3)This one gets a bit strange.
exact solution: x=1/(e^2-1)
approx. solution: x=.156517...
2)x=3
3)This one gets a bit strange.
exact solution: x=1/(e^2-1)
approx. solution: x=.156517...
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1og10 100=2?