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the answer is E
for question 5
however, how do you guys do it? can anyone explain it to me please?
Alteast one birthday a month = 12 automatically
FIVE pairs of twins
3 pairs share birthday in april. Assume ONE pair is already counted in the twelve, so add two.
14.
then 2 more twins (assume already counted)
How do i go about doing this question?
ty
the answer is E
for question 5
however, how do you guys do it? can anyone explain it to me please?
Alteast one birthday a month = 12 automatically
FIVE pairs of twins
3 pairs share birthday in april. Assume ONE pair is already counted in the twelve, so add two.
14.
then 2 more twins (assume already counted)
How do i go about doing this question?
ty
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You're on the right track:
One a month except April makes 11.
There are 3 pairs in April so add 6.
One twin from the other two pairs are in other months so add 2.
At this point there are 19 kids and they have twice as many granddaughters as grandsons.
So we need to figure out the smallest combination of numbers that when you multiply the first number by two you get the second number and together they are 19 or over.
The only combination that meets this requirement is 7 and 14 which together equal 21. 6 and 12 make 18 which is less than the number of grandchildren we know they have so it can't be this answer.
One a month except April makes 11.
There are 3 pairs in April so add 6.
One twin from the other two pairs are in other months so add 2.
At this point there are 19 kids and they have twice as many granddaughters as grandsons.
So we need to figure out the smallest combination of numbers that when you multiply the first number by two you get the second number and together they are 19 or over.
The only combination that meets this requirement is 7 and 14 which together equal 21. 6 and 12 make 18 which is less than the number of grandchildren we know they have so it can't be this answer.
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perfect is exactly right, I was myself unable to solve it at 1st but yes I get what she said
let the 5 twin pairs be named P,Q,R,S,T
it is given that PQR have birthdays in same month of april,
so PQ and R, intotal 6 children have it in april
No of months left = 11
S and T are twins so those even though being 4 children in total can only cover 2 different months
No of months left = 9
so... till now 10 children have been used, PQRS and T, yet 9 months left,
so minimum children for all 12 months = 19
Now by lnear combinations, let the no of boys be x,
then girls will be 2x
Now X must be an integer...
total = 3x
if 3x=19
x=19/3 which is not integer...
next greatest option is 20
20/3 is also not possible
so the least number is 21
as 21/3=7
satisfying the three analogies.
let the 5 twin pairs be named P,Q,R,S,T
it is given that PQR have birthdays in same month of april,
so PQ and R, intotal 6 children have it in april
No of months left = 11
S and T are twins so those even though being 4 children in total can only cover 2 different months
No of months left = 9
so... till now 10 children have been used, PQRS and T, yet 9 months left,
so minimum children for all 12 months = 19
Now by lnear combinations, let the no of boys be x,
then girls will be 2x
Now X must be an integer...
total = 3x
if 3x=19
x=19/3 which is not integer...
next greatest option is 20
20/3 is also not possible
so the least number is 21
as 21/3=7
satisfying the three analogies.